2.应力边界条件 +coS 2o sin X y N a (b) ①p=b-0 0 ==+-cOS 22 = COS p sin2. 应力边界条件 a p x y 0 A q q q (a) cos 2 2 2 p p = + cos 2 2 2 p p = − sin 2 2 p = − = 0 = 0 ① = b → ② = r y o x (b) cos 2 2 2 p p = + sin 2 2 p = − cos 2 2 2 p p = −