1、解，(1)T10.8TN=0.8×280=224Nm 血_1000-1176.471” dh0.85 min.s T-Ti+ GD dn 75 =224+ ×1176.47=459.3H.m) 启动时 375h 375 dh_0-100 2=-15625_r 由0.64 限加3 T=T +GD血-224-7 ×1562.5=536Nm) (2)制动时 375d 375 C4=-B-20-630x0.01484=021 1000 0-220 %= =1047.62(r/) 2、解：(1) C 0.21 0.01484 954C4F955x02T=0035 B R (2) (3)4h,=元-Rw=1047.62-1000=47.62r/mm T=0.84Tw 1=0.841w=0.84×630=5292 1.=104762-001484 n=%一C 0.21 ×5292=1010,22(r/mW (4)E。=CAn=0,21×10I0.22=212.15P) 3.解(1)机城功率Pm-PN+pm+p30000+351+598-0949w (2电磁功率PM-Pm+p2-30949+506-3引455W Sy -Pu-Pa Pas 506 =0.01609 PMP31455 (3Pm=(I-s》M nw=m1-S)=1500×1-0.01609)=1475.9r/mm =955=9556=95×3455 (4)电磁转矩 1500 =200(Nm T=9.55B+L=9.55×35+598=614Nm (5)空载转 14759 (6)输入功率月=P4+P%.+P1=31455+582.3+8242=32861.5W 2 2 1、解：（1）TL=0.8TN=0.8×280=224N.m 启动时 . . ( n.m ) dt dn . GD T T ) min.s r . ( dt . dn L 1176 47 459 3 375 75 224 375 1176 47 0 85 1000 2 = + = +  = = = (2)制动时 . . ( N.m ) dt GD dn T T ) min.s r . ( dt . dn L 1562 5 536 5 375 75 224 375 1562 5 0 64 0 1000 2 = + = − −  = = − − = 2、解：（1） . (r / min) C . U n . . n U I R C e N N N N N a e N 1047 62 0 21 220 0 21 1000 220 630 0 01484 0 = = = = −  = − =   （2） 0 035 9 55 0 21 0 01484 9 55 2 2 . . . . . (C ) R e N a =  = =   （3） n n n . . (r / min)  N = 0 − N =1047 62 −1000 = 47 62 （4） E C n . . . (V ) . . . (r / min) . . I . C R n n I . I . . T . T . a e N a e N a a N L N 0 21 1010 22 212 15 529 2 1010 22 0 21 0 01484 1047 62 0 84 0 84 630 529 2 0 84 0 = =  = = − = −  = = =  = =   3、解（1） 机械功率 Pm=PN+pm+ps=30000+351+598=30949W (2)电磁功率 PM=Pm+pcu2= 30949+506=31455W (3)Pm=（1-s）PM n n ( S ) ( . ) . (r / min) . P p P P P S N M cu M M m N 1 1500 1 0 01609 1475 9 0 01609 31455 506 1 2 = − =  − = = = = − = (4)电磁转矩 . ( N.m ) n P . n P T . M m 200 1500 31455 9 55 9 55 9 55 1 = = =  = （5）空载转矩 . ( N.m ) . . n p p T . m S 6 14 1475 9 351 598 0 9 55 9 55 = + =  + = （6）输入功率 P1 = PM + pFe + pcu1 = 31455 + 582.3+ 824.2 = 32861.5W