S By the substitution rule and the log rule, the left side gives us hn|I|+c1(≠0 Whereas the right side yields(ps being a constant) psdt=pst+c2 Equating the two sides and combining the two constants, we ave ost c (5)  dt = sdt dt dI I  1 By the substitution rule and the log rule, the left side gives us  = + 1 ln | I | c I dI (I  0) Whereas the right side yields ( being a constant) s  = + 2 sdt st c Equating the two sides and combining the two constants, we have ln | I |= st + c ( 5 )