Solution to Example9. 1 population critical interval of T locations of survival time of 065(58 both cat and ra bbit are equal 110),T=127.5, is beyond of T H,: Mi# M2 population locations S0,P<u, Given o=0.05,P<0.05 of survival time of both cat and Ho is rejected, it concludes that the rabbit are not equal survival times of cats and a=0.05 rabbits in the environment Sorting and ranking calculate 2 Rank sums of 2 groups. Take without oxygen might be the li wIth small as T different n1=8<n2=12,s0T=T1=127.5.Solution to Example9.1 ◼ H0 ： M1=M2 population locations of survival time of both cat and rabbit are equal H1： M1 ≠ M2 population locations of survival time of both cat and rabbit are not equal ； a = 0.05 ◼ Sorting and ranking, calculate 2 Rank sums of 2 groups. Take the Ti with small n as T. n1=8<n2=12, so T= T1 =127.5. ◼ critical interval of T0.05 (58- 110),T=127.5, is beyond of Tα , so, P≤α, Given α=0.05, P<0.05; H0 is rejected, it concludes that the survival times of cats and rabbits in the environment without oxygen might be different. 6