Rigid-Body mechanics Instant Screw of rigid-Body motion- example tr(Q)=1+2 cosd=0 φ=120 vect(Q)=sinde sino e To get equation for L, we still need a (Q-1)2(Qa-a) p0= 2(1-co6o) ford≠0Rigid-Body Mechanics • Instant Screw of Rigid-Body Motion – Example tr(Q) = 1 + 2 cos = 0 cos = - vect(Q) = sine = sin = e = To get equation for L, we still need a: 2 1                 = −           − 3 1 3 1 3 1 2 3 1 1 1 2 1 2 3  = 120º                 − 3 1 3 1 3 1