Pascals Principle F Consider F1 moving through a distance d1 How large is the volume of the ↑d liquid displaced? △V=dA This volume determines the displacement of the large piston A △V2=△Vm A A 2=F2d2= Therefore the work done by F1 equals the work done by We have NoT obtained"something for nothing Physics 121: Lecture 20, Pg 10Physics 121: Lecture 20, Pg 10 Pascal’s Principle Consider F1 moving through a distance d1 . How large is the volume of the liquid displaced? F F 1 2 d 2 d 1 A1 A2 V1 = d1A1 V2 = V1 2 1 2 1 A A d = d Therefore the work done by F1 equals the work done by F2 We have NOT obtained “something for nothing”. 1 2 1 1 1 2 2 2 2 1 W A A d A A W = F d = F = This volume determines the displacement of the large piston