单组分系统 S.J.T.0. Phase Transformation and Applications Page 5/36 ·相律分析 F=C-P+2 C=1 P=1,F=2 P≥1；F≥0 P=2,F=1 P=3,F=0 ·物态转变方程式 dP△H N.H 气固或气液 dT TAV P=Aexp RT △H△T 固液 △P= =K·△T AV T SJTU Thermodynamics of Materials Fall 2011 X.J.Jin Lecture 14 Phase diagram IPhase Transformation and Applications S. J. T. U. SJTU Thermodynamics of Materials Fall 2011 © X. J. Jin Lecture 14 Phase diagram I Page 5/36 单组分系统 • 相律分析 • 物态转变方程式 C =1 3, 0 2, 1 1, 2 = = = = = = P F P F F = C − P + 2 P F P ≥1;F ≥ 0 T V H dT dP β α β α Δ Δ = ⎟⎟⎠⎞ ⎜⎜⎝⎛ Δ = − RTH P A βα exp K T T T V H P = ⋅Δ Δ Δ Δ Δ = 1 β α β α 气固或气液 固液