例34(1)的解 (1)(p1Vp2)→3 解:(1Vp2)7 =max{1-(-1),2} =max{1-(1-n),2} max{n1,?2} =max{o(1),a(2)} =ma×{0,1}34(1) (1) (p1 ∨ p2)→p3 : (p1 ∨ p2)σ = max{1 − (¬p1)σ, pσ2} = max{1 − (1 − pσ1), pσ2} = max{pσ1, pσ2} = max{σ(p1), σ(p2)} = max{0, 1} = 1 12