hv> B t=0 0 t=t CA dCA=koC=ko 速率方程 dt e"dC =-kol di A0 CAO-CA=ko t 动力学方程 2 2 A ⎯→ B hv t = 0 C0A 0 t = t CA 0 0 0 k C k dt dC A A  = − = = 速率方程   = − C t C dCA k dt A A 0 0 0 CA0 - CA = k0 t 动力学方程