OP(NO)+O2P"(NO) C"(0)-(N+1)P(NO)NOP (NO) If0>P(NQ+OP (NO) then the expression is negative because the numerator is negative and the denominator is positive If P(No)+OP (No>0 then the numerator is positive-lf N(P(NQ+OP(N)>C(0-P(NO) and then the denominator is negative and the whole expression is again negative Second order conditions require that C"(O(N)-2P(NO)>QP (NO) Only if 0<N(P(NQ)+QP (NO)<C(O-P(NQ is the sign reversal possible. What's going on there?Q N  QP NQQ2PNQ CQN1P NQNQPNQ If 0  P NQ  QPNQ then the expression is negative because the numerator is negative and the denominator is positive. If P NQ  QPNQ  0 then the numerator is positive–If NP NQ  QPNQ  CQ  P NQ and then the denominator is negative and the whole expression is again negative. Second order conditions require that CQN  2P NQ  QPNQ Only if 0  NP NQ  QPNQ  CQ  P NQ is the sign reversal possible. What’s going on there?