P K pi ①'P K;=2/f (2-41) (2-42) K yPs「r-p) exp (2-43 ④P 1=K1x1(i Vi 1 (2-46) K: =f(P,T,x, y) InK: =A-B /(T+Ci) (2-48) lnK1=A1-B1/(T+18-0.197) ∑Kx1 f()=∑K 设T→由PK图查K→∑K,x1-|f(m)≤e →结束 调整T( )       − = RT S i L i V i S i S i i exp V P p ˆ P P K   (2-40) V i L i i K = f f (2-41) L i i L i f x f ~ = (2-42) ( )       − = RT S i L i V i S i S i i i exp V P p P P K    (2-43) yi = Ki xi (i =1,2, c) (2-44) = = c i 1 yi 1 (2-45) = = c i 1 xi 1 (2-46) Ki = f(P,T,x, y) (2-47) lnKi = Ai − Bi (T +Ci ) (2-48) lnKi = Ai − Bi (T +18 −0.19Tb ) (2-49) = = c i 1 Ki xi 1 (2-50) ( ) -1 0 c i 1  i i = f T = K x = (2-51) 设 T ⎯给定P ⎯→ 由 P-T-K 图查 Ki → = c i 1 i i K x → ︳ f(T) ︱≤ε ⎯⎯Y→    i x T →结束 N 调整 T