解(1)Q=△E=C△T 3 ×8.31×(350-300)=623J 2 A=0 (2) AE=3 ×8.31×(350-300)=623J A=PV=4T=8.31×50=416J Q=△E+A=623+416=1019J 目录结束A =0 ( )=623J 2 3 = ×8.31× 350 300 A = pΔV=RΔT = 8.31×50=416J Q =Δ E+A =623+ 416=1019J 解(1) Q =Δ E =CVΔT (2) Δ E ( )=623J 2 3 = ×8.31× 350 300 目录 结束