Example I KN 0.2m 0.05m 2.51 dial di lam P1=F/A=1000/(x0.0252)=5093kPa 2=P1-pg(2.5)=48477kPa f=PA =48477x兀0.12=1523kNExample P1 = F/A = 1000 / ( 0.0252 ) = 509.3 kPa P2 = P1 -  g (2.5) = 484.77 kPa F = P2 A2 = 484.77 x  0.12 = 15.23 kN 2.5m 1 kN F ? 0.2 m diam 0.05 m diam P1 P2