对(4作迭代过程 (k+1) (k) 1 x b °°J (=1,2,…,m;k=0,1,2,…) 设D=aig(a1 1122 丿nn 则(5)式转化为矩阵形式 x(6+1)=x(6)+D(b-Ax( x(k+1)=x()-D-1Ax()+D-1b (k+1) D1(D-4)x()+D-b--------(5) ( ) 1 1 ( 1 ) ( ) ( ) å= + = + - n j k i ij j ii k i k i b a x a x x 对(4)作迭代过程 (i = 1,2,L,n; k = 0,1,2,L) ( , , , ) 11 22 nn 设 D = diag a a L a 则(5)式转化为矩阵形式 ( ) ( k 1 ) ( k ) 1 ( k ) x = x + D b - Ax + - x x D Ax D b ( k + 1 ) ( k ) -1 ( k ) -1 = - + x D D A x D b ( k 1 ) 1 ( k ) 1 ( ) + - - = - + --------(6)