EXAMPLE #2(Contd CONVERSIONS CH4:(60+20)/00=0.80or80% 02:(120+30)200=0.75075% SELECTIVITES CH410C02:6080=0.750r75 CH4t0CO:20/80=0.250r25% Note: The sum of the selectivities for a given key component must sum to 1.0 or 100% CH4toH20:(60+20)/80=l.00r10% 02toCO2:120/50=0.8or80% 02t0CO:30150=0.2or20% /2099 Chemical reactor Characterization9/20/99 Chemical Reactor Characterization 7 EXAMPLE #2 (Cont’d) CONVERSIONS CH4: (60 + 20)/100 = 0.80 or 80% O2: (120 + 30)/200 = 0.75 or 75% SELECTIVITIES CH4 to CO2: 60/80 = 0.75 or 75% CH4 to CO: 20/80 = 0.25 or 25% Note: The sum of the selectivities for a given key component must sum to 1.0 or 100%. CH4 to H2O: (60 + 20)/80 = 1.0 or 100% O2 to CO2: 120/150 = 0.8 or 80% O2 to CO: 30/150 = 0.2 or 20%