正在加载图片...
Count Distinct Elements Input:a sequence,,...,=[N] Output:an estimation of= {出,,} Data stream model:input data item comes one at a time X1 X2 Xn Algorithm 2 ·(e,δ)-estimator: randomized variable Pr1-ek≤2≤1+ez≥1-6 Using only memory equivalent to 5 lines of printed text,you can estimate with a typical accuracy of 5%and in a single pass the total vocabulary of Shakespeare. -Durand and Flajolet 2003Count Distinct Elements • Data stream model: input data item comes one at a time • (ϵ, δ)-estimator: randomized variable Z ̂ Pr [ (1 − ϵ)z ≤ Z ̂ ≤ (1 + ϵ)z ] ≥ 1 − δ Using only memory equivalent to 5 lines of printed text, you can estimate with a typical accuracy of 5% and in a single pass the total vocabulary of Shakespeare. ——Durand and Flajolet 2003 x1 x2 xn Algorithm Z ̂ Input: a sequence Output: an estimation of x1, x2,…, xn ∈ U = [N] z = {x1, x2, …, xn}
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有