Test along the transverse direction t: 1 a+b=- Or rupture Test along the transverse direction z: due to transverse isotropy: b+c= 1 Oi rupture then: 1 a=C=- 267 rupture 1 1 b=3 O1 rupture 267 rupture ■Shear tests: →f=月 Tit rupture 1 T红→e=乏ooc 、1 ■ta→d= Tirupture due to transverse isotropy. Replacing in Equation 14.4: {o-+(o-1 …- -1o,-+1(++s1 2 rupture Or rupture rupture Tiz rupture 2003 by CRC Press LLC
Test along the transverse direction t:
Test along the transverse direction z: due to transverse isotropy: then:
Shear tests: due to transverse isotropy. Replacing in Equation 14.4: a b + 1 st 2 ----- rupture = b c + 1 st 2 ----- rupture = a = c 1 2s
2 ---------- rupture = b 1 st 2 ----- rupture 1 2s
2 --------- rupture = –
t
t Æ f 1 t
t 2 ----- rupture =
ttz Æ e 1 ttz 2 ----- rupture =
t
z Æ d 1 t
t 2 ----- rupture = 1 2s
2 -------- rupture s
– st ( )2 s
– sz ( )2 { } + º º 1 2s
rupture 2 ----------------------- 1 st rupture 2 – ------------------ Ë ¯ Ê ˆ st – sz ( )2 – 1 t
t rupture 2 -------------------- t
t 2 t
z 2 ( ) + ttz 2 ttz rupture 2 + + -------------------- £ 1 TX846_Frame_C14 Page 278 Monday, November 18, 2002 12:30 PM © 2003 by CRC Press LLC