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10.2.Structured Singular Value 189 Theorem 10.6(MAIN LOOP THEOREM)The following are equivalent. 3 2(M22)<1.and u(M)<1 ←→ △87(Fi(MA2)<1e 3 -2(M22)≤1.and ru(M)≤1 sup (F(M△2)≤1∈ △2∈B°△2 Proof.We shall only prove the first part of the equivalence.The proof for the second part is similar. ←Let△i∈△;be given,with(△i)≤l,and define△=diag[△△zl.Obviously △∈△.Now 1 0 det (IM)=detE (10.15) HM21△1I4M22△2 By hypot hesis I u M22A2 is invertible,and hence,det(I u MA)becomes det(IHM2z△2)det(IhM1△1hM2△2(IhM2△2)-1M2△1)∈ Collecting the Ai terms leaves det(IuM△)=det(IuM22△2)det(IuF(M△2)△)∈ (10.16) But,-1(F(M△2)<1and△1∈BA1,so IuF(M-△2)△1 must be nonsingular.. Therefore,ILMA is nonsingular and,by definition,(M)<1. Basically,the argument above is reversed. Again let△1∈B△1and △2∈B△2 be given,and define△=diag[△△l.Thh△∈B△and,by hypothesis, det(I u MA)0.It is easy to verify from the definition of-that (always) -(M)≥max{-(M1)-2(M22)}∈ We can see that2(M22)<1,which givesthat IuM22A2is also nonsingular.Therefore, the expression in (10.16)is valid,giving det(IhM22△2)det(IhF(M△2)△,)=det(IuM△)≠0e Obviously,IhF(M△2)△1 is nonsingular for all△;∈B△i,which indicates that the claim is true. Structured Singular Value ￾ Theorem  MAIN LOOP THEOREM The fol lowing are equivalent ￾￾M  ￾     ￾ M  ￾ and max ￾￾B￾￾￾ F￾ M   ￾ ￾￾M  ￾     ￾ M  ￾ and sup ￾￾ Bo ￾￾ F￾ M   ￾ Proof We shall only prove the rst part of the equivalence The proof for the second part is similar  Let i i be given with  i  ￾ and dene  diag ￾  Obviously   Now det I ￾ M det ￾ I ￾ M￾￾￾ ￾M￾ ￾M￾￾ I ￾ M ￾￾ By hypothesis I ￾ M is invertible and hence det I ￾ M becomes det I ￾ M det I ￾ M￾￾￾ ￾ M￾ I ￾ M￾ M￾￾ Collecting the ￾ terms leaves det I ￾ M det I ￾ M det I ￾ F￾ M  ￾ ￾￾  But ￾￾ F￾ M   ￾ and ￾ B￾ so I ￾ F￾ M  ￾ must be nonsingular Therefore I ￾ M is nonsingular and by denition ￾￾M  ￾  Basically the argument above is reversed Again let ￾ B￾ and  B be given and dene  diag ￾  Then  B and by hypothesis det I ￾ M   It is easy to verify from the denition of ￾ that always ￾ M max f￾￾ M￾￾ ￾ Mg We can see that ￾ M  ￾ which gives that I￾M is also nonsingular Therefore the expression in ￾￾  is valid giving det I ￾ M det I ￾ F￾ M  ￾ det I ￾ M   Obviously I ￾ F￾ M  ￾ is nonsingular for all i Bi  which indicates that the claim is true ￾
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