已知：1=I2=10A PI1⊥PI2a=0.5m 求：B。 B2P 解： Bp BIP=B2P= 4o1 2元a Bp=NBip+B3p =2BIP N2×4×107×10 =5.66×106T 2元×0.50 0 arc tg B22=45° BiP 结東阑 目录 解： B1P =B2P 求：BP = m 2π 0 a 1 I BP = B1P +B2P 2 2 = 2B1P 10 = × 2×4π×10-7× 2π 0.50 = 5.66×10-6 T q = arc tg = B1P B2P 45 0 已知：I1 = I2 =10A PI1 PI2 a = 0.5m I1 I2 P a a B2P B2P BP 结束 目录