DTFT Properties Using the linearity property of Table 3. 2 we then obtain the frequency-domain representation of dovIn]+div[n-1]=poS[n]+p, 8[n-1 as J +dle e P0+p1 Solving the above equation we get V(e/o)=Po t p1e /o JQ 0 +1e Copyright C 2001, S K MitraCopyright © 2001, S. K. Mitra 4 DTFT Properties • Using the linearity property of Table 3.2 we then obtain the frequency-domain representation of as • Solving the above equation we get [ ] [ 1] [ ] [ 1] d0 v n + d1 v n − = p0 n + p1 n −  −   −  + = + j j j j d V e d e V e p p e 0 1 0 1 ( ) ( ) −  −   + + = j j j d d e p p e V e 0 1 0 1 ( )