I RGB 受 Backmarking example 000 40000 290Q 390 50 Suppose no element of the domain of the 5th variable is consistent with the first element of the domain of the first variable 上〓 Backmarking example domain 20 4◎0Backmarking example Variable # 1 2 3 4 5 0 0 0 0 0 B 5 4 3 2 1 i mbl R G 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Remaining domain Suppose no element of the domain of the 5th variable is consistent with the first element of the domain of the first variable Backmarking example Variable # 1 2 3 4 5 0 0 0 0 0 B 5 4 3 2 1 i mbl R G 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 Remaining domain