(数学模型 ★对不同出手速度和出手高度的出手角度和入射角度 2(H-h+o 2) tan B=tan a 2(H-h) tan a g p(ms)hm)a1(度)a2(度)B1(度)B2(度 1.862.409942792553.876320.9213 1963.114740918855820620.1431 8.0 2.063.728139130057.4941196478 2164.2670374017589615193698 1867.697537.049621726126250 1.968.028836.007563.188412.7753 8.5 2.068.336734.521464.1179130240 2168624433.044464927913.3583 1.871.069734.132767142676550 1971.274932.761467.79748.1663 9.0 2.071.470031.388168.40988.7321 2171656130012768984093472v（m/s） h (m) (度) (度) (度) (度) 8.0 1.8 1.9 2.0 2.1 62.4099 63.1147 63.7281 64.2670 42.7925 40.9188 39.1300 37.4017 53.8763 55.8206 57.4941 58.9615 20.9213 20.1431 19.6478 19.3698 8.5 1.8 1.9 2.0 2.1 67.6975 68.0288 68.3367 68.6244 37.5049 36.0075 34.5214 33.0444 62.1726 63.1884 64.1179 64.9279 12.6250 12.7753 13.0240 13.3583 9.0 1.8 1.9 2.0 2.1 71.0697 71.2749 71.4700 71.6561 34.1327 32.7614 31.3881 30.0127 67.1426 67.7974 68.4098 68.9840 7.6550 8.1663 8.7321 9.3472 1  2 1  2 ★对不同出手速度和出手高度的出手角度和入射角度         = + − − + ) 2 ( 2 tan 1 1 2 2 2 2 v gL H h v g gL v  L 2(H h) tan tan −  =  −