解()H=hn+h/2+h (2) H f4 (3)Q1=Q2+Q3+Q4=Q3 由2 21(49 l2(40 13 14 404 8(u 2l2Q2_Q23_1 1.069 =0.661 由391=95=273021 23  5 H4  解 f 1 f 2 f 5 H = h + h + h h f 2 = h f 3 = h f 4 Q1 = Q2 + Q3 + Q4 = Q5 ( 1 ) ( 2 ) ( 3 ) 2 44 44 4 2 33 33 3 2 22 22 2 4 4 4 21   =   =   dQ dl dQ dl dQ d g l       54 2 4 4 4 53 2 3 3 3 52 2 2 2 2 dl Q dl Q d  l Q   = = 1.069 5 24 4 4 2 2 24 =   = dd ll QQ  0.661 5 23 3 3 2 2 23 =   = dd ll QQ  由 2 由 3 1 5 73 2 Q = Q = 2. Q