Chapter 6 Time and Frequency Characterization x(t)=1+cos(2nt+Φ1)+cos(4xt+Φ2)+cos(67t+Φ3) Φ1=①,=①3=0 ①1=4,Φ2=8.3=12 A ①1=6,①2=-27①3=0.93 ①1=12,①2=41,3=-725 ( ) cos( ) cos( ) cos( ) 1 2 3 1 2 1 2 4 6 2 3 x t t t t = + + + + + +       0 1 = 2 = 3 = 4, 8, 12 1 = 2 = 3 = 6, 2 .7, 0.93 1 2 3  =  = −  = 1.2, 4.1, 7.2 1 2 3  =  =  = − Chapter 6 Time and Frequency Characterization