The received on subcarrier ko is y()=7(Oxp(12△f Assume h(=l, w(t=0 (ideal channel), then y() becomes Y()=J 2X(p) 2 rpaf exp(= Afn)The received on subcarrier k0 is ( ) r(t) ( j k f t)dt T Y k T  = −  0 exp 2 1  Assume h(t)=1, w(t)=0 (ideal channel), then Y(k) becomes ( ) ( ) ( ) ( )   − = =  −  T N p X p j p f t j k f t T Y k 0 1 0 exp 2 exp 2 1  