Example: Find Z, and IA 400W Solution: A〖 0. 8 PLeading A2, 300/√3∠0°V/,4004 b 0. 8 PLeading 200 300/√3 300 200W Let van ∠0°p 200 300 =115540°4400=12×0.8∴IA2=289∠3690A 300/√3 3 IA=IA1+IA2=3.87∠26.6°A 300/√3 ∠-36.9°=60∠-36.9°A 2.89Example: Find Z and I A . • 2 Solution: Let V an V  0 3 300 =  • . A / I A  1 155 0 300 3 200 1 = =  • 0.8 3 300 400 = I 2  I A I A I A A  = 1+ 2 = 3.8726.6 • • • Z A   36.9 60 36.9 2.89 300 / 3 2 =  − =  − I A1 • I A2 • a − + I A • . PFleading W 0 8 400 / V  300 30 200W n Z2 a − + I A • − + − + b c 200W . PFleading W 0 8 400 300 / 3V Z2 I A A   2 = 2.8936.9 •