Planned order release-A 2002008080200400400400 Gross reqts.of c for A 2002008080200400400400 Net reqts.of c for A 2002008080200400400400 Time ph.n.reqts.of C for A 20020080 80200400400400 P.O.release of c for A 2002008080200400400400 Planned order release-B 100100 4040100200200200 Gross reqts of c for B 2002008080200400400400 Net reqts.of c for B 2002008080200400400400 Time ph.n.reqts of c for B 200 200 8080200400400400 P.0.release of C for B 200200 8080200400400400 0 P.O.release of C for A&B 200400280160280600800800400 Answer 6 a)SPT sequence minimizes mean flow time.It is 6-5-1-4-2-7-3. b)First order by EDD which is 1-2-5-3-4-7-6. Processing Completion Job Time Time Due Date 3 4 2 6 9 8 Stop. Place job 2 at the end of the current sequence. Processing Completion Job Time Time Due Date V 0 3 4 5 2 5 11 8 13 12 Stop. Place job 3 at the end of the current sequence.Planned order release-A 200 200 80 80 200 400 400 400 Gross reqts. of C for A 200 200 80 80 200 400 400 400 Net reqts. of C for A 200 200 80 80 200 400 400 400 Time ph.n.reqts. of C for A 200 200 80 80 200 400 400 400 P.O. release of C for A 200 200 80 80 200 400 400 400 Planned order release-B 100 100 40 40 100 200 200 200 Gross reqts of C for B 200 200 80 80 200 400 400 400 Net reqts. of C for B 200 200 80 80 200 400 400 400 Time ph. n. reqts of C for B 200 200 80 80 200 400 400 400 P.O. release of C for B 200 200 80 80 200 400 400 400 0 P.O. release of C for A&B 200 400 280 160 280 600 800 800 400 Answer 6 a) SPT sequence minimizes mean flow time. It is 6-5-1-4-2-7-3. b) First order by EDD which is 1-2-5-3-4-7-6. Processing Completion Job Time Time Due Date 1 3 3 4 2 6 9 8 * Stop. Place job 2 at the end of the current sequence. Processing Completion Job Time Time Due Date 1 3 3 4 5 2 5 11 3 8 13 12 * Stop. Place job 3 at the end of the current sequence