Capacity of Bsc I (X;Y)=Hb(Po)-Hb(Pe) H(P)=P log(1/P)+(1-P)log(1/1-P Hb(P)<=1 with equality if P=1/2 C=max po ((X; Y)=Hb(Po)-H(Pe))=1-Hb(Pe Hb(P) C=1-Hb(Pe 1/2 C=0 when P= 1/2 and c 1 when P=0 or P =1Eytan Modiano Slide 6 Capacity of BSC I (X;Y) = Hb (P0) - Hb(Pe) • Hb(P) = P log(1/P) + (1-P) log(1/ 1-P) – Hb(P) <= 1 with equality if P=1/2 C = max P0 {I (X;Y) = Hb (P0) - Hb(Pe)} = 1 - Hb(Pe) C = 0 when Pe = 1/2 and C = 1 when Pe = 0 or Pe=1 0 1/2 1 P Hb(P) 1 0 1/2 1 Pe C = 1 - Hb(Pe) 1