例题：计算下反应式△G° NADH+H++1/202-NAD++H2O 正极反应：1/202+2H+2e=H20 E+°′=0.82 负极反应：NAD+Ht+2e=NADH E。= -0.3 △G°′=-nF△E°/ -2×96485×[0.82-(-0.32)] =-220KJmo1-1例题：计算下反应式ΔG°′ NADH+H++1/2O2====NAD++H2O 正极反应：1/2O2+2H++2e = H2O E +°′= 0.82 负极反应：NAD++H++2e = NADH E -°′= -0.3 ΔG°′=-nFΔE°′ = -2×96485×[0.82-(-0.32)] = -220 KJ·mol-1