由克拉默法则知,方程组有唯一解 81 51 D 81→x 502 2-12 4-76 81 3 27 8-51 190 D2= 108→x D2 0-5-12 76 =108 27由克拉默法则知,方程组有唯一解 0 4 7 6 5 2 1 2 9 3 0 6 8 1 5 1 1 − − − − − − D = =81 = −108 1 0 7 6 0 5 1 2 1 9 0 6 2 8 5 1 2 − − − − − D = D D x 1  1 = 27 81 = =3 D D x 2  2 = 27 −108 = = −4