②Pt,C2(P)|HCl(a)‖HCl(a2)|C2(P),Pt+ (a1>a2) (-)2C(a)-→Cl2(P)+2e (+)Cl2P)+2e-→2CI(a2) 总：2CI(a)一→2Cr(az) dor =an a:=an E=一F (a±)12F 1515 ②(-)Pt, Cl2 (P)│HCl(a1 )‖HCl(a2 )│Cl2 (P), Pt(+) (a1 > a2 ) (-) 2Cl- (a1 ) —→ Cl2 (P) +2e (+) Cl2 (P) +2e —→ 2Cl- (a2 ) 总：2Cl- (a1 ) —→2 Cl- (a2 ) 1/ 2 a a a a Cl H − = + =  = 2 1 1 2 ( ) 2 ( ) a a Ln F RT a a Ln F RT E = − =  