+u1(0+)-0.2A R 3 R u ① a(0)() 4V R i3(0 u1(0)=i(0)R=6V≠0图 l2(0+)=u2(O+)=LC(0)=4V i2(O)=v2(0)/R2=0.2A i(0)=3(0)/R3=0.1A ic(0)=i1(0)-i2(0)-i3(0)=-0.1A (0)=-1(0) +as-C(0)=010 R1 R 2 R3 + 4V - t=0+图 + uS - 0.2 A +uL (0+ )- +u1 (0+ )- i2 (0+ ) iC (0+ ) i3 (0+ ) 1 (0 ) = 1 (0 ) 1 = 6 V + + u i R 2 (0 ) = 3 (0 ) = (0 ) = 4 V + + + u u uC 2 (0 ) = 2 (0 )/ 2 = 0.2A + + i v R C (0 ) = L (0 ) − 2 (0 ) − 3 (0 ) = −0.1A + + + + i i i i (0 ) (0 ) (0 ) 0 L = − 1 + − = + + + u u uS uC 3 (0 ) = 3 (0 )/ 3 = 0.1A + + i u R