6-4 Obtaining the reduced form Solving for 2, +BP++=元+HP+T+v (6) Solving for P O元KT BBBB Rearranging(6), (-)P=(4-a)+K1-+(v-l 2-a K P (8) B-4B-4 C Chris brooks2002,陈磊204© Chris Brooks 2002, 陈磊 2004 6-4 • Solving for Q, (6) • Solving for P, (7) • Rearranging (6), (8) Obtaining the Reduced Form  + P +S + u =  + P +T + v Q S u Q T v             − − − = − − − ( − )P = ( −) +T −S + (v − u) P T S v u = − − + − − − − − −            