ME 357 Power Screw Homework Solutions 1.11-8 Known:Acme thread 5 ~6 7 f=0.15,/.=0.15.d,-16m,2a=29 ueio:FindFfor applied fore2om therec Sol. P=L=1/6=0.1667” seca=- 1 -=1.033 cosa dn=d-0.5*p= 51 =0.5417 812 T.-FdL+md seca 2πd.-uL seca =F05410.1667+0*0.15*0.5417*1.033 2π0.5417-0.15*0.1667*1.033 =0.0696F 015*7 I-F44=F,6-0.0328F) 2 2 .Tu=Te+T.=0.102F T=F·r=6b*2.75=16.5b-im 0.102F=16.51b-im F-161.8bME 357 Power Screw Homework Solutions 1. 11-8 f f F