Integral Results from the N-C Formulas Example 5.1.Consider the function fx)=1+e*sin(4x),the equally spaced quadrature nodes xo-0.0,x1=0.5,x2=1.0,x3=1.5,and x4-=2.0,and the corresponding function values=1.00000,f=1.55152,=0.72159, =0.93765,and fa=1.13390.The step size is h=0.5. fa:00w0+15152=06378 [fk*051000+405152+0.72159=132128 [fd301000+315152+0.72159+093765)=164193 8 fxk÷2X0.3(71.000)+3215152+120.72159)+320.93765)+701.13390)=22944 45 Integral Results from the N-C Formulas Example 5.1. Consider the function f(x)=1+e -x sin(4x), the equally spaced quadrature nodes x0=0.0, x1=0.5,x2=1.0,x3=1.5, and x4=2.0, and the corresponding function values f0=1.00000, f1=1.55152, f2=0.72159, f3=0.93765, and f4=1.13390. The step size is h=0.5. 0.5 0 0.5 ( ) (1.00000 1.55152) 0.63788 2 f x dx  + =  1.0 0 0.5 ( ) (1.00000 4(1.55152) 0.72159) 1.32128 3 f x dx  + + =  1.5 0 3(0.5) ( ) (1.00000 3(1.55152) 3(0.72159) 0.93765) 1.64193 8 f x dx  + + + =  2.0 0 2(0.5) ( ) (7(1.00000) 32(1.55152) 12(0.72159) 32(0.93765) 7(1.13390)) 2.29444 45 f x dx  + + + + = 