812.2 one-dimensional waves and the equation of waves Solution: (a) A=0.04(m)2=0.4(m)/(, 0 v=00Sm/s O=2=0.4z(rads-) afm) The initial phase angle of point 0: po=n 2 y(0,t)=0.04c0s(0.4m+ (b) the wavefunction y(x,t)=0.04c0s04x(t- 0.08 812.2 one-dimensional waves and the equation of waves (c) the oscillatory equation of point P 0.4、兀 甲(xp,1)=0.04c00mx =004c0s0.4m+ (d)the moving directions of points a and b (x,1) 0.04 0.211 (a) 2 0.4 (rad s ) 0.04( ) 0.4(m) −1 = = ⋅ = = π λ ω π λ v A m • a •b x(m) 0.04 Ψ(x,t) o 0.2 P v=0.08m/s Solution: ) 2 (0, ) 0.04 cos( 0.4 π Ψ t = πt + 2 0 π The initial phase angle of point o: ϕ = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = − + 2 ) 0.08 ( , ) 0.04cos 0.4 ( π π x Ψ x t t (b) the wavefunction §12.2 one-dimensional waves and the equation of waves Ψ a b x 0.04 Ψ(x,t) o 0.2 p • • ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = + ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = − + 2 0.04cos 0.4 2 ) 0.08 0.4 ( , ) 0.04cos 0.4 ( π π π π t Ψ x t t P (c) the oscillatory equation of point P (d) the moving directions of points a and b. §12.2 one-dimensional waves and the equation of waves