6-5静电场的能量能量密度第6章静电场中的导体和电介质 2 R In maX e4π£o R1 b2πo SRI n=nmax= 2T CEbr R R W=兀ERh +R dw dRI E,ER(2In e 1)=0 R 十 R,10 R1 m≈607×10 e R ER U=ER In 9.10×103V max R12√6 – 5 静电场的能量 能量密度 第6章静电场中的导体和电介质 max 2π 0 Eb R1 = = 1 2 2 1 2 e 0 b π ln R R W = E R π (2ln 1) 0 d d 1 2 1 2 0 b 1 e = − = R R E R R W m 6.07 10 m e 10 e 3 2 2 1 − − = = R R 0 1 max b 2π R E = 1 2 0 2 e ln 4π R R W = l + + + + - - - - R1 R2 ++ + + + + ++ _ _ _ _ _ _ _ _ 9.10 10 V 2 e ln b 2 3 1 2 max = b 1 = = E R R R U E R