E2=p22+m2c E 讨论:当v<<C时 pc 2 E-E 0 (E+E0)(E-E0) =E(E+E0) k no E Ely k 0 满足对应原理 2EkMoc2 4 0 2 2 2 E = p c + m c E 2 0 m c pc 讨论： 当 v  c 时 ( ) 2 0 0 0 0 0 2 0 2 2 2 2 1 ( ) ( )( ) E m c E E E E E E E E E c p E E k k k = =  + = + = + − = −  0 2 2m p Ek = 满足对应原理