、从氢化热看苯的稳定性 △H=120KJ/mol 2H2 △H=232KJ/mol +3H △H=208KJ/mol △H苯理=3x120=360KJ/mol △H*实=208KJ/mol ZProfessorwangkangchengEmaIl:w518@sohu.com二、从氢化热看苯的稳定性 H2 2H2 3H2 H= _ 120KJ / mol H= _ 232KJ / mol H= _ 208KJ / mol H苯理=3x120=360KJ / mol H苯实=208 KJ / mol