o(1)U RqUE 10×15=5V R2=R1+R220+10 U2-UB5-0.7 C Ra 2 mA c2 lB=2le=2×=1mA +(1+B 200+51==1.5k U 2 U R B U U-U il RRc50× 200 U, EE 5 图P4-6 -200(10 sin at)=2sin ot(vEQ T be bb I U r = r + (1+ )  = + =1.5k 1 26 200 51 i1 i2 o i d o d u d U U U U U A − = = 200 1.5 50 6 = −  = − = − be C r R ( ) Uo = Aud Ui1 −Ui2 200( 10 sin ) 2sin (V) 2 = − − t = t − (1)