对公式变形 13. Define a= nlw to be the()(定义); rearranging(1) produces(将公式变形得到) 公式 We maximize E for each layer, subject to the constraint(2). The calculations are easier if we minimize 1/E.(为了得到最大值,求他倒数的最小值) Neglecting constant factors(忽略常 数), we minimize 公式 使服从约束条件 14. Subject to the constraint(使服从约束条件) 公式 Where B is constant defined in(2). However, as long as we are obeying this constraint, we can write(根据约束条件我们得到) 公式 And thus f depends only on h, the function f is minimized at(求最小值) 公式 At this value of h the constraint reduces to 公式 结果说明 15. This implies (HA) that the harmonic mean of l and w should be 公式 5. This value shows very little loss due to friction.(结果说明) The escape speed with friction is 公式 16. We use a similar process to find the position of the droplet, resulting in 公式 With t=00001 s, error from the approximation is virtually zero 17. We calculated its trajectory(轨道) using 公式 18. For that case, using the same expansion for e as above 公式 19. Solving for t and equating it to the earlier expression for t, we get 公式 20. Recalling that in this equality only n is a function of f, we substitute for n and solve for f. the result is 公式 Asv=., this equation becomes singular(单数的 由语句得到公式 21. The revenue generated by the flight is 公式 24. Then we have对公式变形 13．Define A=nlw to be the ( )（定义）; rearranging (1) produces （将公式变形得到） 公式 We maximize E for each layer, subject to the constraint (2). The calculations are easier if we minimize 1/E.（为了得到最大值，求他倒数的最小值） Neglecting constant factors （忽略常 数）, we minimize 公式 使服从约束条件 14．Subject to the constraint （使服从约束条件） 公式 Where B is constant defined in (2). However, as long as we are obeying this constraint, we can write （根据约束条件我们得到） 公式 And thus f depends only on h , the function f is minimized at （求最小值） 公式 At this value of h, the constraint reduces to 公式 结果说明 15．This implies（暗示） that the harmonic mean of l and w should be 公式 So , in the optimal situation. ……… 5．This value shows very little loss due to friction.（结果说明） The escape speed with friction is 公式 16． We use a similar process to find the position of the droplet, resulting in 公式 With t=0.0001 s, error from the approximation is virtually zero. 17．We calculated its trajectory(轨道) using 公式 18．For that case, using the same expansion for e as above, 公式 19．Solving for t and equating it to the earlier expression for t, we get 公式 20．Recalling that in this equality only n is a function of f, we substitute for n and solve for f. the result is 公式 As v=…, this equation becomes singular (单数的). 由语句得到公式 21．The revenue generated by the flight is 公式 24．Then we have