(2)f(r)=sinx f(x)=sin(x+kt (0)=sih2/0, k=2m 2(-1)mn1,k=2m-1 SInx =x +(-1) 1x2m-1 3!5 (2m-1) +R2m(x) 其中R2m(x) cos(x 2m+1 (2m+1)! 0<6<1) HIGH EDUCATION PRESS 0@8 机动 上页下页返回结味( ) = sin(x + ) ( ) f x k   sin x = x 3! 3 x − 5! 5 x + (2 1)! 2 1 − + − m x m ( ) 2 R x + m 其中 R2m (x) = sin( ) 2 2 1   + + m x 2  k  2 (0) sin ( )  f k k =    = 0, k = 2m ( 1) , k = 2m−1 −1 − m (m =1,2, ) − 1 ( 1) − − m (0  1) 2m+1 x (2m +1)! ( 1) cos( x) m −  机动 目录 上页 下页 返回 结束