△FN=FaO=10629×0.10=1063kN 2=F2+MFN=5979+1063=7042kN V=F+V2=35.87+70.42=10629NN Ek n  = =  = F F  106.29 0.10 10.63kN 2 2 N V F F = +  = + 59.79 10.63=70.42kN 1 1 2 V F V = + = + 35.87 70.42=106.29kN