1= simplify(subs(g,’x',’(2-t^2)/(1+t^2)’) 1=-2/3 (1+x)√2+ 1 -=dt d (x-1)2(x+2) +2)[x-1)f(x+2)]2 dx (x+2 f='y3-(x-1)/(x+2): x=solve(f), dx=simplify(diff(x, 'y)) (2*y3+1)/(y3-1) g=1/((x+2)*y2)*(9*y2/(y^3-1)-2) gl=simplify(subs(g, x','(2*y 3+1)/(1-y 3))) g1=-3/(y3-1) (g1) ans=-1og(y-1)+1/2*1og(y2+y+1)+3(1/2)*atan(1/3*(2*y+1)*3(1/2) In ly-1+In ly tg(2 3(x-12(x+2)g1=simplify(subs(g,'x','(2-t^2)/(1+t^2)')) g1 = -2/3 f='y^3-(x-1)/(x+2)'; x=solve(f), dx=simplify(diff(x,'y')) x =-(2*y^3+1)/(y^3-1); dx = 9*y^2/(y^3-1)^2 g='1/((x+2)*y^2)*(9*y^2/(y^3-1)^2)'; g1=simplify(subs(g,'x','(2*y^3+1)/(1-y^3)')) g1 =-3/(y^3-1) int(g1) ans = -log(y-1)+1/2*log(y^2+y+1)+3^(1/2)*atan(1/3*(2*y+1)*3^(1/2))