5.3 GASEOUS EQUILIBRIA S.J.T.U. Phase Transformation and Applications 02→0 2 aG=AG7-AGa=187800-0=13730U △G°=-RTln2 do =-RT In 002 p △G° Po 187,800 =1.5×10-10 =-22.58 RT (8.314)1000) Since Po+Po,latm Pos =1-Po P。=(1.5×10-10)1-P)/2P。=1.5×10-10 SJTU Thermodynamics of Materials Spring2006©X.J.Jin Lecture 9 Chemical equilibrium llPhase Transformation and Applications S. J. T. U. SJTU Thermodynamics of Materials Spring 2006 © X. J. Jin Lecture 9 Chemical equilibrium II 5.3 GASEOUS EQUILIBRIA Since 2 → OO21 GGG J f Of 800,1870800,187 21 2 0, , =−=Δ−Δ=Δ D D D 2/1 0 2/1 0 2 2 ln ln O PO P −=Δ RTG −= RT α D α 58.22 )1000)(314.8( 800,187 ln 2/10 2 −= −= Δ −= RT G P P O D 10 2/1 0 105.1 2 − ×= PO P O 1atmPP0 2 + = 1 0 2 O = − PP 2/1 0 10 0 P −×= P )1)(105.1( − 10 0 105.1 − P ×=