EX4 Vector graphical analysis method VB3=VB2+VB3B2 Mag: ?√？ Dire: √∥BC Direction of V2:b2→b3o3=μpb3/lCB b3 p 3 03 b2 C Find VBa? EX4 Vector graphical analysis method 7入N aB3=anB3+a'83=aB2+a9382 +akB3B2 Mag:？o23lc?ho2 ak B3B2 2WVB38203 Dire:?B→C√B→A∥BC Found: VB3B2 aB3=μapb3,a'B3B2=μakb3B→C A a3=aB3/lc=μab3”b3'/lgc 01 Bi 3 p 3 C Find Ags? b3 1010 Vector graphical analysis method EX4 VB3＝VB2+VB3B2 Direction of VB3B2 : b2b3 ω3 = μvpb3 / lCB Mag： Dire： ? √ √ √ ? ∥BC p b2 b3 Find VB3? B 1 3 2 A C ω3 ω1 Vector graphical analysis method EX4 + ak aB3 = a B3B2 n B3+ at B3 = aB2+ ar B3B2 Find AB3? ak B3B2 VB3B2 Mag： Dire： ? ? ω2 3lBC B→C ? √ l1ω21 B→A ? ∥BC 2VB3B2ω3 √ b’ 2 k’ b’ 3 b” 3 p’ aB3 ＝μap’ b3 ’ , α3＝at B3 /lBC＝μab3’’b3’ /lBC ar B3B2 ＝μak’ b3 ’ B → C Found： B 1 3 2 A C ω3 ω1