★统一积分变量 l=actg(π-a)=-actga dl a csc'ada r a/sina B=∫Im@ )4π 2 2 sin ada I sina 2 sin a -ma1s咖a (c0sz1-c0sa2) B cosa-cosa? 4元4统一积分变量 a dl P l 1 2 r dB I O X Y l = actg( −) = −actg dl a csc d 2 = r = a sin = 2 2 2 0 4 sin ad I sin a sin = 2 0 4 r I sin dl B = 2 1 sin 4 0 I d a (cos cos ) 4 1 2 0 = − a I B (cos cos ) 4 1 2 0 = − a I