Evaluation of ons of Residue Theorem 留数定理 (要点) f(2)d=2m∑resf( k=1 【证】绕每个奇点bk作闭合曲线 ⊙ k,使№k均在G内,且互不交叠 则根据复连通区域 Cauchy定理及 Laurent展开的 系数公式,即得 r(22=∑4()=2m2 k=1 JokResidue theorem Evaluation of Definite Integrals Residue theorem Some Applications of Residue Theorem Residue at Infinity 3ê½n (:) I C f(z)dz = 2πi Xn k=1 res f(bk) =y>7zÛ:bk4Ü γk§¦γkþ3GS§
pØU KâEëÏ«Cauchy½n9LaurentÐm Xêú I ª§= C f(z)dz = P n k=1 I γk f(z)dz =2πi P n k=1 a (k) −1 =2πi P n k=1 res f(bk) C. S. Wu 1ù 3ê½n9ÙA^()