QUESTION 3 k=∑kxP =(0.120.1)+(0.09k0.60+(0.060.2 0.0180.0540.015 =0.080r8.7% △(-x x Pr (0.120.080.15+(0.090.08)0.60(0.060.08)0.25 =√0.00016336.0000059.00018225 =√0.000351 =0.01871.8735%July 200 3 QUESTION 3 ( ) ( ) ( ) = 0 .0 8 7o r 8 .7 % = 0 .0 1 8+ 0 .0 5 4+ 0 .0 1 5 = 0 .1 2 0 .1 5 + 0 .0 9 0 .6 0 + 0 .0 6 0 .2 5 k = k P r ni=1 i i     ( ) ( ) ( ) ( ) 0 .0 1 8 7 3 5o r 1 .8 7 3 5 % 0 .0 0 0 3 5 1 0 .0 0 0 1 6 3 3 50 .0 0 0 0 0 5 40 .0 0 0 1 8 2 2 5 0 .1 2- 0 .0 8 7 0 .1 5 0 .0 9- 0 .0 8 7 0 .6 0 0 .0 6- 0 .0 8 7 0 .2 5 k - k P r 2 2 2 ni 1 i 2 k i === + + = + + =   = 