解： (1) 对于钠光dsino=一po=0.2 对于1光dsin0=元1一p=0.22° S1n0九=s1n0.22y 11=s1n0o sin.0.20×5894 =684.2×104(nm) (2) 放入水中后 2 22-n sing= sin go_sin0.2° n 1.33 p=0.15 结束返回解： dsinj 0 =l =684.2×10-4 (nm) dsinj =l1 l1 l sinj 0 sinj = l2 = l n sin ×5894 sin0.20 0.220 = = sinj 0 sinj n = sin0.20 1.33 j =0.150 j0 =0.20 j =0.220 (1) 对于钠光 对于l1光 (2) 放入水中后 结束 返回